純C 字串 BASE64 互轉/轉換 (C_Base64)

資料來源:https://www.jianshu.com/p/125c4bbed460

GITHUB: https://github.com/jash-git/C_Base64

字串長度變化規則: 設字串長度為n ，長度為 ⌈n/3⌉ *4    ⌈⌉  代表上取整

#include <stdio.h>
#include <stdlib.h>
#include "base64.h"
//https://www.jianshu.com/p/125c4bbed460
int main()
{
    // insert code here...

    char str1[] = "tablename";
    char str2[200] = {0}; //注意长度要给够
    int len = 0;
    base64_encode(str1,(int)strlen(str1),str2,&len);
    printf("%s, len = %d\n", str2, len);


    char str3[200] = {0};
    base64_decode(str2, (int)strlen(str2), str3, &len);

    printf("%s, len = %d\n", str3, len);
    return 0;
}

#ifndef BASE64_H_INCLUDED
#define BASE64_H_INCLUDED

#include <stdio.h>

#if __cplusplus
extern "C"{
#endif

    int base64_encode(const char *indata, int inlen, char *outdata, int *outlen);
    int base64_decode(const char *indata, int inlen, char *outdata, int *outlen);

#if __cplusplus
}
#endif

#endif // BASE64_H_INCLUDED

//
//  base64.c
//  base64
//
//  Created by guofu on 2017/5/25.
//  Copyright © 2017年 guofu. All rights reserved.
//
/**
 *  转解码过程
 *  3 * 8 = 4 * 6; 3字节占24位, 4*6=24
 *  先将要编码的转成对应的ASCII值
 *  如编码: s 1 3
 *  对应ASCII值为: 115 49 51
 *  对应二进制为: 01110011 00110001 00110011
 *  将其6个分组分4组: 011100 110011 000100 110011
 *  而计算机是以8bit存储, 所以在每组的高位补两个0如下:
 *  00011100 00110011 00000100 00110011对应:28 51 4 51
 *  查找base64 转换表 对应 c z E z
 *
 *  解码
 *  c z E z
 *  对应ASCII值为 99 122 69 122
 *  对应表base64_suffix_map的值为 28 51 4 51
 *  对应二进制值为 00011100 00110011 00000100 00110011
 *  依次去除每组的前两位, 再拼接成3字节
 *  即: 01110011 00110001 00110011
 *  对应的就是s 1 3
 */

#include "base64.h"

#include <stdio.h>
#include <stdlib.h>

// base64 转换表, 共64个
static const char base64_alphabet[] = {
    'A', 'B', 'C', 'D', 'E', 'F', 'G',
    'H', 'I', 'J', 'K', 'L', 'M', 'N',
    'O', 'P', 'Q', 'R', 'S', 'T',
    'U', 'V', 'W', 'X', 'Y', 'Z',
    'a', 'b', 'c', 'd', 'e', 'f', 'g',
    'h', 'i', 'j', 'k', 'l', 'm', 'n',
    'o', 'p', 'q', 'r', 's', 't',
    'u', 'v', 'w', 'x', 'y', 'z',
    '0', '1', '2', '3', '4', '5', '6', '7', '8', '9',
    '+', '/'};

// 解码时使用
static const unsigned char base64_suffix_map[256] = {
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 253, 255,
    255, 253, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 253, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255,  62, 255, 255, 255,  63,
    52,  53,  54,  55,  56,  57,  58,  59,  60,  61, 255, 255,
    255, 254, 255, 255, 255,   0,   1,   2,   3,   4,   5,   6,
    7,   8,   9,  10,  11,  12,  13,  14,  15,  16,  17,  18,
    19,  20,  21,  22,  23,  24,  25, 255, 255, 255, 255, 255,
    255,  26,  27,  28,  29,  30,  31,  32,  33,  34,  35,  36,
    37,  38,  39,  40,  41,  42,  43,  44,  45,  46,  47,  48,
    49,  50,  51, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255, 255,
    255, 255, 255, 255 };

static char cmove_bits(unsigned char src, unsigned lnum, unsigned rnum) {
    src <<= lnum; // src = src << lnum;
    src >>= rnum; // src = src >> rnum;
    return src;
}

int base64_encode(const char *indata, int inlen, char *outdata, int *outlen) {

    int ret = 0; // return value
    if (indata == NULL || inlen == 0) {
        return ret = -1;
    }

    int in_len = 0; // 源字符串长度, 如果in_len不是3的倍数, 那么需要补成3的倍数
    int pad_num = 0; // 需要补齐的字符个数, 这样只有2, 1, 0(0的话不需要拼接, )
    if (inlen % 3 != 0) {
        pad_num = 3 - inlen % 3;
    }
    in_len = inlen + pad_num; // 拼接后的长度, 实际编码需要的长度(3的倍数)

    int out_len = in_len * 8 / 6; // 编码后的长度

    char *p = outdata; // 定义指针指向传出data的首地址

    //编码, 长度为调整后的长度, 3字节一组
    int i;
    for (i = 0; i < in_len; i+=3) {
        int value = *indata >> 2; // 将indata第一个字符向右移动2bit(丢弃2bit)
        char c = base64_alphabet[value]; // 对应base64转换表的字符
        *p = c; // 将对应字符(编码后字符)赋值给outdata第一字节

        //处理最后一组(最后3字节)的数据
        if (i == inlen + pad_num - 3 && pad_num != 0) {
            if(pad_num == 1) {
                *(p + 1) = base64_alphabet[(int)(cmove_bits(*indata, 6, 2) + cmove_bits(*(indata + 1), 0, 4))];
                *(p + 2) = base64_alphabet[(int)cmove_bits(*(indata + 1), 4, 2)];
                *(p + 3) = '=';
            } else if (pad_num == 2) { // 编码后的数据要补两个 '='
                *(p + 1) = base64_alphabet[(int)cmove_bits(*indata, 6, 2)];
                *(p + 2) = '=';
                *(p + 3) = '=';
            }
        } else { // 处理正常的3字节的数据
            *(p + 1) = base64_alphabet[cmove_bits(*indata, 6, 2) + cmove_bits(*(indata + 1), 0, 4)];
            *(p + 2) = base64_alphabet[cmove_bits(*(indata + 1), 4, 2) + cmove_bits(*(indata + 2), 0, 6)];
            *(p + 3) = base64_alphabet[*(indata + 2) & 0x3f];
        }

        p += 4;
        indata += 3;
    }

    if(outlen != NULL) {
        *outlen = out_len;
    }

    return ret;
}


int base64_decode(const char *indata, int inlen, char *outdata, int *outlen) {

    int ret = 0;
    if (indata == NULL || inlen <= 0 || outdata == NULL || outlen == NULL) {
        return ret = -1;
    }
    if (inlen % 4 != 0) { // 需要解码的数据不是4字节倍数
        return ret = -2;
    }

    int t = 0, x = 0, y = 0, i = 0;
    unsigned char c = 0;
    int g = 3;

    while (indata[x] != 0) {
        // 需要解码的数据对应的ASCII值对应base64_suffix_map的值
        c = base64_suffix_map[indata[x++]];
        if (c == 255) return -1;// 对应的值不在转码表中
        if (c == 253) continue;// 对应的值是换行或者回车
        if (c == 254) { c = 0; g--; }// 对应的值是'='
        t = (t<<6) | c; // 将其依次放入一个int型中占3字节
        if (++y == 4) {
            outdata[i++] = (unsigned char)((t>>16)&0xff);
            if (g > 1) outdata[i++] = (unsigned char)((t>>8)&0xff);
            if (g > 2) outdata[i++] = (unsigned char)(t&0xff);
            y = t = 0;
        }
    }
    if (outlen != NULL) {
        *outlen = i;
    }
    return ret;
}